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Need Help on This [ TSQL ]

HI Sanila ! You may get the desired output using below query;SELECT COUNT(CASE WHEN GQ.QID IS NULL THEN 1 END) AS Count FROM dbo.QUESTION Q LEFT JOIN dbo.GROUP_QUESTION GQ ON GQ.QID = Q.QID --1 SELECT...

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Need Help on This [ TSQL ]

INSERT [dbo].[GROUP_QUESTION] ([GROUP], [QID]) VALUES (N'G3', N'Q3') INSERT [dbo].[GROUP_QUESTION] ([GROUP], [QID]) VALUES (NULL, NULL) INSERT [dbo].[GROUP_QUESTION] ([GROUP], [QID]) VALUES (N'G3',...

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Need Help on This [ TSQL ]

OR this will do : SELECT COUNT(*) FROM dbo.QUESTION Q        WHERE Q.QID NOT IN  (SELECT QID FROM GROUP_QUESTION WHERE QID IS NOT NULL)Thanks and regards, Rishabh K

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Need Help on This [ TSQL ]

Because you can't compare NULL values. For NULL values you have to do the comparisation with IS or IS NOT not with IN, =, >, <NULL is undefined.Try:SELECT COUNT(*) FROM dbo.QUESTION        WHERE...

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Need Help on This [ TSQL ]

Because of QID in GROUP_QUESTION contains NULLSELECT COUNT(*) FROM dbo.QUESTION       WHERE QID WHERE NOT EXISTS(SELECT * FROM GROUP_QUESTION Q WHERE Q.QID=QUESTION.QID  )Best Regards,Uri Dimant SQL...

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Need Help on This [ TSQL ]

Why the answer is coming 0 instead of 1 ??CREATE TABLE [dbo].[QUESTION](         [QID] [varchar](10) NULL,         [DESC] [varchar](100) NULL ) ON [PRIMARY] INSERT [dbo].[QUESTION] ([QID], [DESC])...

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